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102+x(4x+6)=180
We move all terms to the left:
102+x(4x+6)-(180)=0
We add all the numbers together, and all the variables
x(4x+6)-78=0
We multiply parentheses
4x^2+6x-78=0
a = 4; b = 6; c = -78;
Δ = b2-4ac
Δ = 62-4·4·(-78)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{321}}{2*4}=\frac{-6-2\sqrt{321}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{321}}{2*4}=\frac{-6+2\sqrt{321}}{8} $
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