102/3m=m

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Solution for 102/3m=m equation:



102/3m=m
We move all terms to the left:
102/3m-(m)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
We add all the numbers together, and all the variables
-1m+102/3m=0
We multiply all the terms by the denominator
-1m*3m+102=0
Wy multiply elements
-3m^2+102=0
a = -3; b = 0; c = +102;
Δ = b2-4ac
Δ = 02-4·(-3)·102
Δ = 1224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1224}=\sqrt{36*34}=\sqrt{36}*\sqrt{34}=6\sqrt{34}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{34}}{2*-3}=\frac{0-6\sqrt{34}}{-6} =-\frac{6\sqrt{34}}{-6} =-\frac{\sqrt{34}}{-1} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{34}}{2*-3}=\frac{0+6\sqrt{34}}{-6} =\frac{6\sqrt{34}}{-6} =\frac{\sqrt{34}}{-1} $

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