104,04+144=c2

Solution for 104,04+144=c2 equation:

104.04+144=c2

We move all terms to the left:

104.04+144-(c2)=0

We add all the numbers together, and all the variables

-1c^2+248.04=0

a = -1; b = 0; c = +248.04;
Δ = b2-4ac
Δ = 02-4·(-1)·248.04
Δ = 992.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{992.16}}{2*-1}=\frac{0-\sqrt{992.16}}{-2}
=-\frac{\sqrt{}}{-2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{992.16}}{2*-1}=\frac{0+\sqrt{992.16}}{-2}
=\frac{\sqrt{}}{-2}
$