104=(2w-3)*w

Solution for 104=(2w-3)*w equation:

104=(2w-3)*w

We move all terms to the left:

104-((2w-3)*w)=0


We calculate terms in parentheses: -((2w-3)*w), so:

(2w-3)*w

We multiply parentheses

2w^2-3w

Back to the equation:

-(2w^2-3w)


We get rid of parentheses

-2w^2+3w+104=0

a = -2; b = 3; c = +104;
Δ = b2-4ac
Δ = 32-4·(-2)·104
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-29}{2*-2}=\frac{-32}{-4}
=+8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+29}{2*-2}=\frac{26}{-4}
=-6+1/2
$