104=(5y-2)+(4y)+(5y-2)+(4y)

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Solution for 104=(5y-2)+(4y)+(5y-2)+(4y) equation: 



104=(5y-2)+(4y)+(5y-2)+(4y)

We move all terms to the left:

104-((5y-2)+(4y)+(5y-2)+(4y))=0



We calculate terms in parentheses: -((5y-2)+4y+(5y-2)+4y), so:

(5y-2)+4y+(5y-2)+4y

We add all the numbers together, and all the variables

8y+(5y-2)+(5y-2)

We get rid of parentheses

8y+5y+5y-2-2

We add all the numbers together, and all the variables

18y-4

Back to the equation:

-(18y-4)



We get rid of parentheses

-18y+4+104=0

We add all the numbers together, and all the variables

-18y+108=0

We move all terms containing y to the left, all other terms to the right

-18y=-108

y=-108/-18

y=+6

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