104=1/2(x)(3x+2)

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Solution for 104=1/2(x)(3x+2) equation: 



104=1/2(x)(3x+2)

We move all terms to the left:

104-(1/2(x)(3x+2))=0



Domain of the equation: 2x(3x+2))!=0

x∈R



We multiply all the terms by the denominator


-(1+104*2x(3x+2))=0



We calculate terms in parentheses: -(1+104*2x(3x+2)), so:

1+104*2x(3x+2)

determiningTheFunctionDomain
104*2x(3x+2)+1

Wy multiply elements

208x(3+1

Back to the equation:

-(208x(3+1)



We add all the numbers together, and all the variables

-(208x4=0

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