104=2(3z+1)+2(4z+2)

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Solution for 104=2(3z+1)+2(4z+2) equation:


Simplifying
104 = 2(3z + 1) + 2(4z + 2)

Reorder the terms:
104 = 2(1 + 3z) + 2(4z + 2)
104 = (1 * 2 + 3z * 2) + 2(4z + 2)
104 = (2 + 6z) + 2(4z + 2)

Reorder the terms:
104 = 2 + 6z + 2(2 + 4z)
104 = 2 + 6z + (2 * 2 + 4z * 2)
104 = 2 + 6z + (4 + 8z)

Reorder the terms:
104 = 2 + 4 + 6z + 8z

Combine like terms: 2 + 4 = 6
104 = 6 + 6z + 8z

Combine like terms: 6z + 8z = 14z
104 = 6 + 14z

Solving
104 = 6 + 14z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-14z' to each side of the equation.
104 + -14z = 6 + 14z + -14z

Combine like terms: 14z + -14z = 0
104 + -14z = 6 + 0
104 + -14z = 6

Add '-104' to each side of the equation.
104 + -104 + -14z = 6 + -104

Combine like terms: 104 + -104 = 0
0 + -14z = 6 + -104
-14z = 6 + -104

Combine like terms: 6 + -104 = -98
-14z = -98

Divide each side by '-14'.
z = 7

Simplifying
z = 7

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