104x2+99x-180=0

Solution for 104x2+99x-180=0 equation:

104x^2+99x-180=0

a = 104; b = 99; c = -180;
Δ = b2-4ac
Δ = 992-4·104·(-180)
Δ = 84681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{84681}=291$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-291}{2*104}=\frac{-390}{208}
=-1+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+291}{2*104}=\frac{192}{208}
=12/13
$