105+-9t+-16t2=0

Solution for 105+-9t+-16t2=0 equation:

105+-9t+-16t^2=0

We add all the numbers together, and all the variables

-16t^2-9t=0

a = -16; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-16)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-16}=\frac{18}{-32}
=-9/16
$