105-45=3(b-15)

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Solution for 105-45=3(b-15) equation: 



105-45=3(b-15)

We move all terms to the left:

105-45-(3(b-15))=0

We add all the numbers together, and all the variables

-(3(b-15))+60=0



We calculate terms in parentheses: -(3(b-15)), so:

3(b-15)

We multiply parentheses

3b-45

Back to the equation:

-(3b-45)



We get rid of parentheses

-3b+45+60=0

We add all the numbers together, and all the variables

-3b+105=0

We move all terms containing b to the left, all other terms to the right

-3b=-105

b=-105/-3

b=+35

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