105/35=15/n

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Solution for 105/35=15/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

105/35 = 15/n // - 15/n

105/35-(15/n) = 0

105/35-15*n^-1 = 0

-15*n^-1 = -3 // : -15

n^-1 = 1/5

-1 < 0

1/(n^1) = 1/5 // * n^1

1 = 1/5*n^1 // : 1/5

5 = n^1

n = 5

n = 5

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