105/35=27/n

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Solution for 105/35=27/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

105/35 = 27/n // - 27/n

105/35-(27/n) = 0

105/35-27*n^-1 = 0

-27*n^-1 = -3 // : -27

n^-1 = 1/9

-1 < 0

1/(n^1) = 1/9 // * n^1

1 = 1/9*n^1 // : 1/9

9 = n^1

n = 9

n = 9

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