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1050=(x-12)(x+18)(6)
We move all terms to the left:
1050-((x-12)(x+18)(6))=0
We multiply parentheses ..
-((+x^2+18x-12x-216)6)+1050=0
We calculate terms in parentheses: -((+x^2+18x-12x-216)6), so:We get rid of parentheses
(+x^2+18x-12x-216)6
We multiply parentheses
6x^2+108x-72x-1296
We add all the numbers together, and all the variables
6x^2+36x-1296
Back to the equation:
-(6x^2+36x-1296)
-6x^2-36x+1296+1050=0
We add all the numbers together, and all the variables
-6x^2-36x+2346=0
a = -6; b = -36; c = +2346;
Δ = b2-4ac
Δ = -362-4·(-6)·2346
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-240}{2*-6}=\frac{-204}{-12} =+17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+240}{2*-6}=\frac{276}{-12} =-23 $
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