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105=-12n(-5n)
We move all terms to the left:
105-(-12n(-5n))=0
We calculate terms in parentheses: -(-12n(-5n)), so:a = -60; b = 0; c = +105;
-12n(-5n)
We multiply parentheses
60n^2
Back to the equation:
-(60n^2)
Δ = b2-4ac
Δ = 02-4·(-60)·105
Δ = 25200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25200}=\sqrt{3600*7}=\sqrt{3600}*\sqrt{7}=60\sqrt{7}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{7}}{2*-60}=\frac{0-60\sqrt{7}}{-120} =-\frac{60\sqrt{7}}{-120} =-\frac{\sqrt{7}}{-2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{7}}{2*-60}=\frac{0+60\sqrt{7}}{-120} =\frac{60\sqrt{7}}{-120} =\frac{\sqrt{7}}{-2} $
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