105=-4(3+4a)+5

Solution for 105=-4(3+4a)+5 equation:

105=-4(3+4a)+5

We move all terms to the left:

105-(-4(3+4a)+5)=0

We add all the numbers together, and all the variables

-(-4(4a+3)+5)+105=0


We calculate terms in parentheses: -(-4(4a+3)+5), so:

-4(4a+3)+5

We multiply parentheses

-16a-12+5

We add all the numbers together, and all the variables

-16a-7

Back to the equation:

-(-16a-7)


We get rid of parentheses

16a+7+105=0

We add all the numbers together, and all the variables

16a+112=0

We move all terms containing a to the left, all other terms to the right

16a=-112

a=-112/16

a=-7