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1064=(20+x)(30+x)
We move all terms to the left:
1064-((20+x)(30+x))=0
We add all the numbers together, and all the variables
-((x+20)(x+30))+1064=0
We multiply parentheses ..
-((+x^2+30x+20x+600))+1064=0
We calculate terms in parentheses: -((+x^2+30x+20x+600)), so:We get rid of parentheses
(+x^2+30x+20x+600)
We get rid of parentheses
x^2+30x+20x+600
We add all the numbers together, and all the variables
x^2+50x+600
Back to the equation:
-(x^2+50x+600)
-x^2-50x-600+1064=0
We add all the numbers together, and all the variables
-1x^2-50x+464=0
a = -1; b = -50; c = +464;
Δ = b2-4ac
Δ = -502-4·(-1)·464
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-66}{2*-1}=\frac{-16}{-2} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+66}{2*-1}=\frac{116}{-2} =-58 $
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