106=(3x+10)+(3x+10)+(2x+6)

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Solution for 106=(3x+10)+(3x+10)+(2x+6) equation: 



106=(3x+10)+(3x+10)+(2x+6)

We move all terms to the left:

106-((3x+10)+(3x+10)+(2x+6))=0



We calculate terms in parentheses: -((3x+10)+(3x+10)+(2x+6)), so:

(3x+10)+(3x+10)+(2x+6)

We get rid of parentheses

3x+3x+2x+10+10+6

We add all the numbers together, and all the variables

8x+26

Back to the equation:

-(8x+26)



We get rid of parentheses

-8x-26+106=0

We add all the numbers together, and all the variables

-8x+80=0

We move all terms containing x to the left, all other terms to the right

-8x=-80

x=-80/-8

x=+10

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