106=(3y+22)+4y

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Solution for 106=(3y+22)+4y equation:



106=(3y+22)+4y
We move all terms to the left:
106-((3y+22)+4y)=0
We calculate terms in parentheses: -((3y+22)+4y), so:
(3y+22)+4y
We add all the numbers together, and all the variables
4y+(3y+22)
We get rid of parentheses
4y+3y+22
We add all the numbers together, and all the variables
7y+22
Back to the equation:
-(7y+22)
We get rid of parentheses
-7y-22+106=0
We add all the numbers together, and all the variables
-7y+84=0
We move all terms containing y to the left, all other terms to the right
-7y=-84
y=-84/-7
y=+12

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