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106=c2
We move all terms to the left:
106-(c2)=0
We add all the numbers together, and all the variables
-1c^2+106=0
a = -1; b = 0; c = +106;
Δ = b2-4ac
Δ = 02-4·(-1)·106
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{106}}{2*-1}=\frac{0-2\sqrt{106}}{-2} =-\frac{2\sqrt{106}}{-2} =-\frac{\sqrt{106}}{-1} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{106}}{2*-1}=\frac{0+2\sqrt{106}}{-2} =\frac{2\sqrt{106}}{-2} =\frac{\sqrt{106}}{-1} $
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