106=x(2)+(41-x)(4)

Solution for 106=x(2)+(41-x)(4) equation:

106=x(2)+(41-x)(4)

We move all terms to the left:

106-(x(2)+(41-x)(4))=0

We add all the numbers together, and all the variables

-(x2+(-1x+41)4)+106=0


We calculate terms in parentheses: -(x2+(-1x+41)4), so:

x2+(-1x+41)4

We add all the numbers together, and all the variables

x^2+(-1x+41)4

We multiply parentheses

x^2-4x+164

Back to the equation:

-(x^2-4x+164)


We get rid of parentheses

-x^2+4x-164+106=0

We add all the numbers together, and all the variables

-1x^2+4x-58=0

a = -1; b = 4; c = -58;
Δ = b2-4ac
Δ = 42-4·(-1)·(-58)
Δ = -216
Delta is less than zero, so there is no solution for the equation