107=8(1+2b)+3

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Solution for 107=8(1+2b)+3 equation:



107=8(1+2b)+3
We move all terms to the left:
107-(8(1+2b)+3)=0
We add all the numbers together, and all the variables
-(8(2b+1)+3)+107=0
We calculate terms in parentheses: -(8(2b+1)+3), so:
8(2b+1)+3
We multiply parentheses
16b+8+3
We add all the numbers together, and all the variables
16b+11
Back to the equation:
-(16b+11)
We get rid of parentheses
-16b-11+107=0
We add all the numbers together, and all the variables
-16b+96=0
We move all terms containing b to the left, all other terms to the right
-16b=-96
b=-96/-16
b=+6

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