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108+2/3x=x
We move all terms to the left:
108+2/3x-(x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+2/3x+108=0
We multiply all the terms by the denominator
-1x*3x+108*3x+2=0
Wy multiply elements
-3x^2+324x+2=0
a = -3; b = 324; c = +2;
Δ = b2-4ac
Δ = 3242-4·(-3)·2
Δ = 105000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{105000}=\sqrt{2500*42}=\sqrt{2500}*\sqrt{42}=50\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(324)-50\sqrt{42}}{2*-3}=\frac{-324-50\sqrt{42}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(324)+50\sqrt{42}}{2*-3}=\frac{-324+50\sqrt{42}}{-6} $
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