1080=(x+8)(2x+8)

Solution for 1080=(x+8)(2x+8) equation:

1080=(x+8)(2x+8)

We move all terms to the left:

1080-((x+8)(2x+8))=0

We multiply parentheses ..

-((+2x^2+8x+16x+64))+1080=0


We calculate terms in parentheses: -((+2x^2+8x+16x+64)), so:

(+2x^2+8x+16x+64)

We get rid of parentheses

2x^2+8x+16x+64

We add all the numbers together, and all the variables

2x^2+24x+64

Back to the equation:

-(2x^2+24x+64)


We get rid of parentheses

-2x^2-24x-64+1080=0

We add all the numbers together, and all the variables

-2x^2-24x+1016=0

a = -2; b = -24; c = +1016;
Δ = b2-4ac
Δ = -242-4·(-2)·1016
Δ = 8704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8704}=\sqrt{256*34}=\sqrt{256}*\sqrt{34}=16\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16\sqrt{34}}{2*-2}=\frac{24-16\sqrt{34}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16\sqrt{34}}{2*-2}=\frac{24+16\sqrt{34}}{-4}
$