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1086=6x(x+17)
We move all terms to the left:
1086-(6x(x+17))=0
We calculate terms in parentheses: -(6x(x+17)), so:We get rid of parentheses
6x(x+17)
We multiply parentheses
6x^2+102x
Back to the equation:
-(6x^2+102x)
-6x^2-102x+1086=0
a = -6; b = -102; c = +1086;
Δ = b2-4ac
Δ = -1022-4·(-6)·1086
Δ = 36468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36468}=\sqrt{36*1013}=\sqrt{36}*\sqrt{1013}=6\sqrt{1013}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-6\sqrt{1013}}{2*-6}=\frac{102-6\sqrt{1013}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+6\sqrt{1013}}{2*-6}=\frac{102+6\sqrt{1013}}{-12} $
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