108=(x+2)(x-1)

Solution for 108=(x+2)(x-1) equation:

108=(x+2)(x-1)

We move all terms to the left:

108-((x+2)(x-1))=0

We multiply parentheses ..

-((+x^2-1x+2x-2))+108=0


We calculate terms in parentheses: -((+x^2-1x+2x-2)), so:

(+x^2-1x+2x-2)

We get rid of parentheses

x^2-1x+2x-2

We add all the numbers together, and all the variables

x^2+x-2

Back to the equation:

-(x^2+x-2)


We get rid of parentheses

-x^2-x+2+108=0

We add all the numbers together, and all the variables

-1x^2-1x+110=0

a = -1; b = -1; c = +110;
Δ = b2-4ac
Δ = -12-4·(-1)·110
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-21}{2*-1}=\frac{-20}{-2}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+21}{2*-1}=\frac{22}{-2}
=-11
$