108=1/2(2x+4)(x+5)

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Solution for 108=1/2(2x+4)(x+5) equation: 



108=1/2(2x+4)(x+5)

We move all terms to the left:

108-(1/2(2x+4)(x+5))=0



Domain of the equation: 2(2x+4)(x+5))!=0

x∈R



We multiply parentheses ..

-(1/2(+2x^2+10x+4x+20))+108=0

We multiply all the terms by the denominator


-(1+108*2(+2x^2+10x+4x+20))=0



We calculate terms in parentheses: -(1+108*2(+2x^2+10x+4x+20)), so:

1+108*2(+2x^2+10x+4x+20)

determiningTheFunctionDomain
108*2(+2x^2+10x+4x+20)+1

Wy multiply elements

216x(++1

We use the square of the difference formula

216x(+1

Back to the equation:

-(216x(+1)



We add all the numbers together, and all the variables

-(216x1=0

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