108=2x+96+(x+12)

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Solution for 108=2x+96+(x+12) equation: 



108=2x+96+(x+12)

We move all terms to the left:

108-(2x+96+(x+12))=0



We calculate terms in parentheses: -(2x+96+(x+12)), so:

2x+96+(x+12)

determiningTheFunctionDomain
2x+(x+12)+96

We get rid of parentheses

2x+x+12+96

We add all the numbers together, and all the variables

3x+108

Back to the equation:

-(3x+108)



We get rid of parentheses

-3x-108+108=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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