108=4(4v+3)

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Solution for 108=4(4v+3) equation: 



108=4(4v+3)

We move all terms to the left:

108-(4(4v+3))=0



We calculate terms in parentheses: -(4(4v+3)), so:

4(4v+3)

We multiply parentheses

16v+12

Back to the equation:

-(16v+12)



We get rid of parentheses

-16v-12+108=0

We add all the numbers together, and all the variables

-16v+96=0

We move all terms containing v to the left, all other terms to the right

-16v=-96

v=-96/-16

v=+6

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