108=6x+3(4x-12)

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Solution for 108=6x+3(4x-12) equation: 



108=6x+3(4x-12)

We move all terms to the left:

108-(6x+3(4x-12))=0



We calculate terms in parentheses: -(6x+3(4x-12)), so:

6x+3(4x-12)

We multiply parentheses

6x+12x-36

We add all the numbers together, and all the variables

18x-36

Back to the equation:

-(18x-36)



We get rid of parentheses

-18x+36+108=0

We add all the numbers together, and all the variables

-18x+144=0

We move all terms containing x to the left, all other terms to the right

-18x=-144

x=-144/-18

x=+8

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