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108=u2
We move all terms to the left:
108-(u2)=0
We add all the numbers together, and all the variables
-1u^2+108=0
a = -1; b = 0; c = +108;
Δ = b2-4ac
Δ = 02-4·(-1)·108
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*-1}=\frac{0-12\sqrt{3}}{-2} =-\frac{12\sqrt{3}}{-2} =-\frac{6\sqrt{3}}{-1} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*-1}=\frac{0+12\sqrt{3}}{-2} =\frac{12\sqrt{3}}{-2} =\frac{6\sqrt{3}}{-1} $
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