109=1-4(8v+5)

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Solution for 109=1-4(8v+5) equation: 



109=1-4(8v+5)

We move all terms to the left:

109-(1-4(8v+5))=0



We calculate terms in parentheses: -(1-4(8v+5)), so:

1-4(8v+5)

determiningTheFunctionDomain
-4(8v+5)+1

We multiply parentheses

-32v-20+1

We add all the numbers together, and all the variables

-32v-19

Back to the equation:

-(-32v-19)



We get rid of parentheses

32v+19+109=0

We add all the numbers together, and all the variables

32v+128=0

We move all terms containing v to the left, all other terms to the right

32v=-128

v=-128/32

v=-4

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