10=((t*t)-t)/2

Solution for 10=((t*t)-t)/2 equation:

10=((t*t)-t)/2

We move all terms to the left:

10-(((t*t)-t)/2)=0

We add all the numbers together, and all the variables

-(((+t*t)-t)/2)+10=0

We multiply all the terms by the denominator


-(((+t*t)-t)+10*2)=0


We calculate terms in parentheses: -(((+t*t)-t)+10*2), so:

((+t*t)-t)+10*2

We add all the numbers together, and all the variables

((+t*t)-t)+20


We calculate terms in parentheses: +((+t*t)-t), so:

(+t*t)-t

We add all the numbers together, and all the variables

-1t+(+t*t)

We get rid of parentheses

-1t+t*t

Wy multiply elements

t^2-1t

Back to the equation:

+(t^2-1t)


We get rid of parentheses

t^2-1t+20

Back to the equation:

-(t^2-1t+20)


We get rid of parentheses

-t^2+1t-20=0

We add all the numbers together, and all the variables

-1t^2+t-20=0

a = -1; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·(-1)·(-20)
Δ = -79
Delta is less than zero, so there is no solution for the equation