10=(1+t)2

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Solution for 10=(1+t)2 equation: 



10=(1+t)2

We move all terms to the left:

10-((1+t)2)=0

We add all the numbers together, and all the variables

-((t+1)2)+10=0



We calculate terms in parentheses: -((t+1)2), so:

(t+1)2

We multiply parentheses

2t+2

Back to the equation:

-(2t+2)



We get rid of parentheses

-2t-2+10=0

We add all the numbers together, and all the variables

-2t+8=0

We move all terms containing t to the left, all other terms to the right

-2t=-8

t=-8/-2

t=+4

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