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10=(1.5/x)x
We move all terms to the left:
10-((1.5/x)x)=0
Domain of the equation: x)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1.5/x)x)+10=0
We multiply all the terms by the denominator
-((+1.5+10*x)x)=0
We calculate terms in parentheses: -((+1.5+10*x)x), so:We get rid of parentheses
(+1.5+10*x)x
We add all the numbers together, and all the variables
(10x+1.5)x
We multiply parentheses
10x^2+1.5x
Back to the equation:
-(10x^2+1.5x)
-10x^2-1.5x=0
a = -10; b = -1.5; c = 0;
Δ = b2-4ac
Δ = -1.52-4·(-10)·0
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{2.25}}{2*-10}=\frac{1.5-\sqrt{2.25}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{2.25}}{2*-10}=\frac{1.5+\sqrt{2.25}}{-20} $
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