10=(1/9-1-3x)27

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Solution for 10=(1/9-1-3x)27 equation: 



10=(1/9-1-3x)27

We move all terms to the left:

10-((1/9-1-3x)27)=0



Domain of the equation: 9-1-3x)27)!=0

We move all terms containing x to the left, all other terms to the right

-3x)27)!=-8

x!=-8/1

x!=-8

x∈R



We add all the numbers together, and all the variables

-((-3x+1/9-1)27)+10=0

We multiply all the terms by the denominator


-((-3x+1+10*9-1)27)=0



We calculate terms in parentheses: -((-3x+1+10*9-1)27), so:

(-3x+1+10*9-1)27

We add all the numbers together, and all the variables

(-3x+90)27

We multiply parentheses

-81x+2430

Back to the equation:

-(-81x+2430)



We get rid of parentheses

81x-2430=0

We move all terms containing x to the left, all other terms to the right

81x=2430

x=2430/81

x=30

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