10=(2/5-3x)

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Solution for 10=(2/5-3x) equation: 



10=(2/5-3x)

We move all terms to the left:

10-((2/5-3x))=0



Domain of the equation: 5-3x))!=0

We move all terms containing x to the left, all other terms to the right

-3x))!=-5

x!=-5/1

x!=-5

x∈R



We add all the numbers together, and all the variables

-((-3x+2/5))+10=0

We multiply all the terms by the denominator


-((-3x+2+10*5))=0



We calculate terms in parentheses: -((-3x+2+10*5)), so:

(-3x+2+10*5)

We add all the numbers together, and all the variables

(-3x+52)

We get rid of parentheses

-3x+52

Back to the equation:

-(-3x+52)



We get rid of parentheses

3x-52=0

We move all terms containing x to the left, all other terms to the right

3x=52

x=52/3

x=17+1/3

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