10=(2x+3)=71

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Solution for 10=(2x+3)=71 equation: 



10=(2x+3)=71

We move all terms to the left:

10-((2x+3))=0



We calculate terms in parentheses: -((2x+3)), so:

(2x+3)

We get rid of parentheses

2x+3

Back to the equation:

-(2x+3)



We get rid of parentheses

-2x-3+10=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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