10=(2x-6)/2

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Solution for 10=(2x-6)/2 equation: 



10=(2x-6)/2

We move all terms to the left:

10-((2x-6)/2)=0

We multiply all the terms by the denominator


-((2x-6)+10*2)=0



We calculate terms in parentheses: -((2x-6)+10*2), so:

(2x-6)+10*2

We add all the numbers together, and all the variables

(2x-6)+20

We get rid of parentheses

2x-6+20

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We get rid of parentheses

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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