10=(3x+2)/5

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Solution for 10=(3x+2)/5 equation: 



10=(3x+2)/5

We move all terms to the left:

10-((3x+2)/5)=0

We multiply all the terms by the denominator


-((3x+2)+10*5)=0



We calculate terms in parentheses: -((3x+2)+10*5), so:

(3x+2)+10*5

We add all the numbers together, and all the variables

(3x+2)+50

We get rid of parentheses

3x+2+50

We add all the numbers together, and all the variables

3x+52

Back to the equation:

-(3x+52)



We get rid of parentheses

-3x-52=0

We move all terms containing x to the left, all other terms to the right

-3x=52

x=52/-3

x=-17+1/3

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