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10=(3x-4)/(x-8)
We move all terms to the left:
10-((3x-4)/(x-8))=0
Domain of the equation: (x-8))!=0We multiply all the terms by the denominator
x∈R
-((3x-4)+10*(x-8))=0
We calculate terms in parentheses: -((3x-4)+10*(x-8)), so:We get rid of parentheses
(3x-4)+10*(x-8)
We multiply parentheses
(3x-4)+10x-80
We get rid of parentheses
3x+10x-4-80
We add all the numbers together, and all the variables
13x-84
Back to the equation:
-(13x-84)
-13x+84=0
We move all terms containing x to the left, all other terms to the right
-13x=-84
x=-84/-13
x=6+6/13
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