10=(3x-5)/2

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Solution for 10=(3x-5)/2 equation: 



10=(3x-5)/2

We move all terms to the left:

10-((3x-5)/2)=0

We multiply all the terms by the denominator


-((3x-5)+10*2)=0



We calculate terms in parentheses: -((3x-5)+10*2), so:

(3x-5)+10*2

We add all the numbers together, and all the variables

(3x-5)+20

We get rid of parentheses

3x-5+20

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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