10=(a/2)-5

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Solution for 10=(a/2)-5 equation: 



10=(a/2)-5

We move all terms to the left:

10-((a/2)-5)=0

We add all the numbers together, and all the variables

-((+a/2)-5)+10=0

We multiply all the terms by the denominator


-((+a+10*2)-5)=0



We calculate terms in parentheses: -((+a+10*2)-5), so:

(+a+10*2)-5

We add all the numbers together, and all the variables

(a+20)-5

We get rid of parentheses

a+20-5

We add all the numbers together, and all the variables

a+15

Back to the equation:

-(a+15)



We get rid of parentheses

-a-15=0

We add all the numbers together, and all the variables

-1a-15=0

We move all terms containing a to the left, all other terms to the right

-a=15

a=15/-1

a=-15

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