10=(c-8+20)

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Solution for 10=(c-8+20) equation:



10=(c-8+20)
We move all terms to the left:
10-((c-8+20))=0
We add all the numbers together, and all the variables
-((c+12))+10=0
We calculate terms in parentheses: -((c+12)), so:
(c+12)
We get rid of parentheses
c+12
Back to the equation:
-(c+12)
We get rid of parentheses
-c-12+10=0
We add all the numbers together, and all the variables
-1c-2=0
We move all terms containing c to the left, all other terms to the right
-c=2
c=2/-1
c=-2

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