10=(z/2)+7

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Solution for 10=(z/2)+7 equation: 



10=(z/2)+7

We move all terms to the left:

10-((z/2)+7)=0

We add all the numbers together, and all the variables

-((+z/2)+7)+10=0

We multiply all the terms by the denominator


-((+z+10*2)+7)=0



We calculate terms in parentheses: -((+z+10*2)+7), so:

(+z+10*2)+7

We add all the numbers together, and all the variables

(z+20)+7

We get rid of parentheses

z+20+7

We add all the numbers together, and all the variables

z+27

Back to the equation:

-(z+27)



We get rid of parentheses

-z-27=0

We add all the numbers together, and all the variables

-1z-27=0

We move all terms containing z to the left, all other terms to the right

-z=27

z=27/-1

z=-27

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