10=-10(3-i)

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Solution for 10=-10(3-i) equation: 



10=-10(3-i)

We move all terms to the left:

10-(-10(3-i))=0

We add all the numbers together, and all the variables

-(-10(-1i+3))+10=0



We calculate terms in parentheses: -(-10(-1i+3)), so:

-10(-1i+3)

We multiply parentheses

10i-30

Back to the equation:

-(10i-30)



We get rid of parentheses

-10i+30+10=0

We add all the numbers together, and all the variables

-10i+40=0

We move all terms containing i to the left, all other terms to the right

-10i=-40

i=-40/-10

i=+4

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