10=-2/3(9+12b)

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Solution for 10=-2/3(9+12b) equation: 



10=-2/3(9+12b)

We move all terms to the left:

10-(-2/3(9+12b))=0



Domain of the equation: 3(9+12b))!=0

b∈R



We add all the numbers together, and all the variables

-(-2/3(12b+9))+10=0

We multiply all the terms by the denominator


-(-2+10*3(12b+9))=0



We calculate terms in parentheses: -(-2+10*3(12b+9)), so:

-2+10*3(12b+9)

determiningTheFunctionDomain
10*3(12b+9)-2

Wy multiply elements

30b(1-2

Back to the equation:

-(30b(1-2)



We add all the numbers together, and all the variables

-(30b(-1)=0



We calculate terms in parentheses: -(30b(-1), so:

30b(-1





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30b(-1





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