10=-3(-3+4)-(2+3b)

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Solution for 10=-3(-3+4)-(2+3b) equation: 



10=-3(-3+4)-(2+3b)

We move all terms to the left:

10-(-3(-3+4)-(2+3b))=0

We add all the numbers together, and all the variables

-(-31-(3b+2))+10=0



We calculate terms in parentheses: -(-31-(3b+2)), so:

-31-(3b+2)

determiningTheFunctionDomain
-(3b+2)-31

We get rid of parentheses

-3b-2-31

We add all the numbers together, and all the variables

-3b-33

Back to the equation:

-(-3b-33)



We get rid of parentheses

3b+33+10=0

We add all the numbers together, and all the variables

3b+43=0

We move all terms containing b to the left, all other terms to the right

3b=-43

b=-43/3

b=-14+1/3

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