10=-3(-3b+4)-(2+3b)

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Solution for 10=-3(-3b+4)-(2+3b) equation: 



10=-3(-3b+4)-(2+3b)

We move all terms to the left:

10-(-3(-3b+4)-(2+3b))=0

We add all the numbers together, and all the variables

-(-3(-3b+4)-(3b+2))+10=0



We calculate terms in parentheses: -(-3(-3b+4)-(3b+2)), so:

-3(-3b+4)-(3b+2)

We multiply parentheses

9b-(3b+2)-12

We get rid of parentheses

9b-3b-2-12

We add all the numbers together, and all the variables

6b-14

Back to the equation:

-(6b-14)



We get rid of parentheses

-6b+14+10=0

We add all the numbers together, and all the variables

-6b+24=0

We move all terms containing b to the left, all other terms to the right

-6b=-24

b=-24/-6

b=+4

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