10=-3(22-b)+2(b-2)

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Solution for 10=-3(22-b)+2(b-2) equation:


Simplifying
10 = -3(22 + -1b) + 2(b + -2)
10 = (22 * -3 + -1b * -3) + 2(b + -2)
10 = (-66 + 3b) + 2(b + -2)

Reorder the terms:
10 = -66 + 3b + 2(-2 + b)
10 = -66 + 3b + (-2 * 2 + b * 2)
10 = -66 + 3b + (-4 + 2b)

Reorder the terms:
10 = -66 + -4 + 3b + 2b

Combine like terms: -66 + -4 = -70
10 = -70 + 3b + 2b

Combine like terms: 3b + 2b = 5b
10 = -70 + 5b

Solving
10 = -70 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
10 + -5b = -70 + 5b + -5b

Combine like terms: 5b + -5b = 0
10 + -5b = -70 + 0
10 + -5b = -70

Add '-10' to each side of the equation.
10 + -10 + -5b = -70 + -10

Combine like terms: 10 + -10 = 0
0 + -5b = -70 + -10
-5b = -70 + -10

Combine like terms: -70 + -10 = -80
-5b = -80

Divide each side by '-5'.
b = 16

Simplifying
b = 16

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