10=-35/2+b

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Solution for 10=-35/2+b equation: 



10=-35/2+b

We move all terms to the left:

10-(-35/2+b)=0



Domain of the equation: 2+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-2

b!=-2/1

b!=-2

b∈R



We add all the numbers together, and all the variables

-(+b-35/2)+10=0

We get rid of parentheses

-b+10+35/2=0

We multiply all the terms by the denominator


-b*2+35+10*2=0

We add all the numbers together, and all the variables

-b*2+55=0

Wy multiply elements

-2b+55=0

We move all terms containing b to the left, all other terms to the right

-2b=-55

b=-55/-2

b=27+1/2

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